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My question is if I have 2 delta connected 11kv syncro-generators supplying a common 3000kw load at 0.8PF. How do I determine the excitation voltage of G1?
The impedances are G1=(0.56+j1.03) and G2=(0.4+j1.5)
The excitation current of G1 is adjusted to deliver 150A lagging and the governors are set so load is shared equally between both machines.
Am I correct (or totally wrong)?<pre>
Given G1 delivers 150A.(angle)0 deg
G1 impedance is (0.56+j1.03) OHMS
and V1 is 11000V.(angle)36.87 deg
than E=V+ZI = 11160.14V.(angle)37.25 deg</pre>
The impedances are G1=(0.56+j1.03) and G2=(0.4+j1.5)
The excitation current of G1 is adjusted to deliver 150A lagging and the governors are set so load is shared equally between both machines.
Am I correct (or totally wrong)?<pre>
Given G1 delivers 150A.(angle)0 deg
G1 impedance is (0.56+j1.03) OHMS
and V1 is 11000V.(angle)36.87 deg
than E=V+ZI = 11160.14V.(angle)37.25 deg</pre>